The function \(f(x) = -2x^2 + 2x + 4\) is a quadratic equation. When graphed, quadratic equations form a distinctive U-shaped or inverted U-shaped curve known as a parabola. This analysis will explore the essential properties of this specific function, providing a clear understanding of its mathematical behavior and graphical representation.
To fully understand this function, we begin by examining its fundamental components and form.
The given function \(f(x) = -2x^2 + 2x + 4\) is already in the standard form of a quadratic equation, which is:
\[ f(x) = ax^2 + bx + c \]By comparing our function to the standard form, we can identify the coefficients:
These coefficients are crucial as they determine the shape, position, and orientation of the parabola.
The coefficient 'a' dictates whether the parabola opens upwards or downwards.
In our case, \(a = -2\), which is negative. Therefore, the parabola for \(f(x) = -2x^2 + 2x + 4\) opens downwards. This implies that the parabola has a highest point, known as the maximum.
A typical parabolic curve, illustrating key features such as the vertex and axis of symmetry.
Several key features define the specific characteristics of the parabola associated with \(f(x) = -2x^2 + 2x + 4\). These include the vertex, axis of symmetry, and intercepts.
The vertex is the point where the parabola reaches its maximum (or minimum) value. Since our parabola opens downwards, the vertex represents its highest point.
The x-coordinate of the vertex \((h, k)\) is found using the formula:
\[ h = -\frac{b}{2a} \]Substituting our values \(a = -2\) and \(b = 2\):
\[ h = -\frac{2}{2(-2)} = -\frac{2}{-4} = 0.5 \]To find the y-coordinate (\(k\)), we substitute this x-value back into the function \(f(x)\):
\[ k = f(0.5) = -2(0.5)^2 + 2(0.5) + 4 \] \[ k = -2(0.25) + 1 + 4 \] \[ k = -0.5 + 1 + 4 \] \[ k = 4.5 \]Thus, the vertex of the parabola is at the point \((0.5, 4.5)\). This is the maximum value of the function.
A quadratic function can also be expressed in vertex form: \(f(x) = a(x-h)^2 + k\). Using our values for \(a\), \(h\), and \(k\):
\[ f(x) = -2(x - 0.5)^2 + 4.5 \]This form directly shows the vertex coordinates and the direction of opening.
The axis of symmetry is a vertical line that passes through the vertex, dividing the parabola into two mirror-image halves. The equation for the axis of symmetry is given by \(x = h\).
For our function, the axis of symmetry is \(x = 0.5\).
Intercepts are the points where the parabola crosses the x-axis and y-axis.
The y-intercept occurs when \(x = 0\). We can find it by substituting \(x=0\) into the function:
\[ f(0) = -2(0)^2 + 2(0) + 4 = 0 + 0 + 4 = 4 \]So, the y-intercept is at the point \((0, 4)\).
The x-intercepts, also known as the roots or zeros of the function, occur when \(f(x) = 0\). To find them, we need to solve the quadratic equation:
\[ -2x^2 + 2x + 4 = 0 \]We can simplify this equation by dividing all terms by -2:
\[ x^2 - x - 2 = 0 \]This simplified quadratic equation can be solved by factoring. We look for two numbers that multiply to -2 and add to -1. These numbers are -2 and +1.
\[ (x - 2)(x + 1) = 0 \]Setting each factor to zero gives the solutions for x:
Therefore, the x-intercepts are at the points \((-1, 0)\) and \((2, 0)\).
Alternatively, the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) could be used on the original equation \(-2x^2 + 2x + 4 = 0\):
\[ x = \frac{-2 \pm \sqrt{2^2 - 4(-2)(4)}}{2(-2)} \] \[ x = \frac{-2 \pm \sqrt{4 + 32}}{-4} \] \[ x = \frac{-2 \pm \sqrt{36}}{-4} \] \[ x = \frac{-2 \pm 6}{-4} \]This gives two solutions:
\[ x_1 = \frac{-2 + 6}{-4} = \frac{4}{-4} = -1 \] \[ x_2 = \frac{-2 - 6}{-4} = \frac{-8}{-4} = 2 \]These results confirm the x-intercepts found by factoring.
To sketch the graph of \(f(x) = -2x^2 + 2x + 4\), we plot the key points we've found:
Knowing the parabola opens downwards and is symmetric about the line \(x=0.5\), we can sketch a smooth curve through these points. For instance, the point \((0,4)\) is 0.5 units to the left of the axis of symmetry. Due to symmetry, there's a corresponding point 0.5 units to the right, at \(x = 0.5 + 0.5 = 1\). The y-value at \(x=1\) is \(f(1) = -2(1)^2 + 2(1) + 4 = -2 + 2 + 4 = 4\). So, \((1,4)\) is another point on the parabola.
The domain and range describe the set of all possible input (x) and output (y) values for the function.
The table below consolidates the key characteristics of the quadratic function \(f(x) = -2x^2 + 2x + 4\):
Feature | Value/Description |
---|---|
Equation | \(f(x) = -2x^2 + 2x + 4\) |
Type of Function | Quadratic |
Shape of Graph | Parabola |
Direction of Opening | Downwards (since \(a = -2 < 0\)) |
Vertex \((h, k)\) | \((0.5, 4.5)\) (Maximum point) |
Axis of Symmetry | \(x = 0.5\) |
Y-intercept | \((0, 4)\) |
X-intercepts (Roots) | \((-1, 0)\) and \((2, 0)\) |
Domain | All real numbers, \((-\infty, \infty)\) |
Range | \(f(x) \le 4.5\), or \((-\infty, 4.5]\) |
This radar chart provides a conceptual overview of the relative ease and clarity associated with analyzing different aspects of the quadratic function \(f(x) = -2x^2 + 2x + 4\). Higher scores (on a scale potentially up to 10) indicate greater straightforwardness in determination or understanding. The values are subjective analytical assessments.
The chart visually represents that identifying the Y-intercept is typically the most straightforward, while finding roots and sketching the complete graph might involve a few more steps, though still quite manageable for this function.
Quadratic functions, like the one we've analyzed, are fundamental in algebra. Understanding how to graph them, particularly by identifying the vertex and intercepts, is a key skill. The following video provides a helpful overview of graphing quadratic functions, focusing on the vertex form, which is closely related to the standard form characteristics we've discussed.
This video complements our analysis by visually demonstrating the graphing process and reinforcing concepts such as the vertex's role in determining the parabola's shape and position. While our function \(f(x) = -2x^2 + 2x + 4\) was analyzed from its standard form, converting it to vertex form (\(f(x) = -2(x - 0.5)^2 + 4.5\)) directly reveals the vertex \((0.5, 4.5)\), as discussed earlier.
This mindmap provides a visual summary of the core components and characteristics of the quadratic function \(f(x) = -2x^2 + 2x + 4\), branching out from the main function to its type, graphical features, and key calculated values.
This visual tool helps to connect the various pieces of information discussed, offering a holistic view of the function's properties.
To deepen your understanding of quadratic functions and related concepts, consider exploring these topics: