In linear regression, the primary goal is to estimate the relationship between a dependent variable (Y) and an independent variable (X). The relationship is typically modeled as:
$$ y = \beta x + \epsilon $$
where:
The selection of X-values significantly impacts the precision and reliability of the estimated β. Optimal selection minimizes the variance of the estimator, leading to a more accurate representation of the underlying relationship between X and Y.
The variance of the estimated slope (\(\hat{\beta}\)) is inversely proportional to the variance of the X-values. Mathematically, the variance of \(\hat{\beta}\) is given by:
$$ \text{Var}(\hat{\beta}) = \frac{\sigma^2}{\sum_{i=1}^n (x_i - \bar{x})^2} $$
To minimize \(\text{Var}(\hat{\beta})\), it is essential to maximize the sum \(\sum (x_i - \bar{x})^2\). This necessitates spreading the X-values as widely as possible within the given constraints.
Placing data points at the extremes of the X range (i.e., -1 and 1) maximizes the spread and variance of X-values. For instance, allocating 12 points at -1 and 12 points at 1 ensures the highest possible variance within the range:
Configuration | Sum of Squared Deviations | Variance of \(\hat{\beta}\) |
---|---|---|
12 at x = -1 and 12 at x = 1 | 24 | \(\frac{\sigma^2}{24}\) |
All 24 at x = 0 | 0 | Undefined (Infinite Variance) |
Mixed allocation (e.g., 8 at -1, 8 at 0, 8 at 1) | 16 | \(\frac{\sigma^2}{16}\) |
As illustrated, the configuration with X-values at the extremes provides the highest sum of squared deviations (24), thereby offering the lowest possible variance for \(\hat{\beta}\).
Ensuring symmetry by evenly splitting X-values between the extreme points not only maximizes variance but also maintains balance in the regression model. This symmetry reduces the covariance between the intercept and slope estimates, leading to a more stable and unbiased estimate of \(\beta\).
Concentrating multiple X-values around a single point or within a narrow range diminishes the overall variance of X, thereby inflating the variance of \(\hat{\beta}\). Such clustering undermines the precision of the regression model.
For example, allocating 18 points at x = 0 and 6 points at x = 1 results in a lower sum of squared deviations (12), compared to the optimal configuration. This leads to a higher variance for \(\hat{\beta}\), making the estimate less reliable.
Including X-values within the intermediate range (e.g., 0 or other values between -1 and 1) reduces the spread and overall variance. This approach is suboptimal for minimizing \(\text{Var}(\hat{\beta})\) and does not leverage the full potential of the available data points.
Generate X-Values: Allocate 12 data points at x = -1 and 12 data points at x = 1. This ensures maximum variance.
Compute Y-Values: For each X-value, calculate the corresponding Y-value using the formula:
$$ y = \beta x + \epsilon $$
where \(\epsilon\) is drawn from a normal distribution with mean 0 and fixed variance.
Perform Linear Regression: Using the generated (X, Y) pairs, execute linear regression to estimate \(\hat{\beta}\).
The variance of the estimator \(\hat{\beta}\) is given by:
$$ \text{Var}(\hat{\beta}) = \frac{\sigma^2}{\sum_{i=1}^n (x_i - \bar{x})^2} $$
By selecting X-values at -1 and 1, we maximize the denominator, thereby minimizing \(\text{Var}(\hat{\beta})\). This leads to a more precise estimate of the true parameter \(\beta\).
import numpy as np
import statsmodels.api as sm
# Parameters
beta = 2.0
sigma = 1.0
n = 24
# Generate X-values
x = np.array([-1]*12 + [1]*12)
# Generate Y-values
epsilon = np.random.normal(0, sigma, n)
y = beta * x + epsilon
# Add intercept
X = sm.add_constant(x)
# Perform linear regression
model = sm.OLS(y, X)
results = model.fit()
# Estimated beta
beta_hat = results.params[1]
print(f"Estimated beta: {beta_hat}")
This Python code demonstrates the generation of X and Y values, followed by performing linear regression to estimate \(\beta\).
The optimal selection of X-values at the extreme points ensures that the estimator \(\hat{\beta}\) has the lowest possible variance. This translates to a more precise and reliable estimate of the true parameter \(\beta\).
By evenly distributing X-values at -1 and 1, the data remains symmetric around the mean (\(\bar{x} = 0\)). This balance reduces potential biases in the regression model and ensures that the estimate of \(\beta\) is unbiased.
Allocating all 24 data points between the two extreme values maximizes the information derived from each data point, thereby enhancing the efficiency of the regression analysis.
Configuration | Sum of Squared Deviations (\(\sum (x_i - \bar{x})^2\)) | Variance of \(\hat{\beta}\) (\(\frac{\sigma^2}{\sum (x_i - \bar{x})^2}\)) | Precision of \(\hat{\beta}\) |
---|---|---|---|
12 at x = -1 and 12 at x = 1 | 24 | \(\frac{\sigma^2}{24}\) | Highest |
8 at x = -1, 8 at x = 0, 8 at x = 1 | 16 | \(\frac{\sigma^2}{16}\) | Moderate |
All 24 at x = 0 | 0 | Infinite | Undefined |
18 at x = -1 and 6 at x = 1 | 18 | \(\frac{\sigma^2}{18}\) | High |
The table demonstrates that the optimal configuration (12 at -1 and 12 at 1) yields the highest sum of squared deviations, resulting in the lowest variance for \(\hat{\beta}\) and the highest precision.
To achieve the most accurate and precise estimate of the regression coefficient \(\beta\) in a linear model, the selection of X-values plays a pivotal role. By allocating an equal number of data points to the extreme ends of the allowed X range (e.g., 12 at \(x = -1\) and 12 at \(x = 1\)), one maximizes the variance of X and consequently minimizes the variance of the estimator \(\hat{\beta}\). This optimal design leads to a more reliable and unbiased estimation of the underlying linear relationship.